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Python 计算笛�尔积

计算多个集�的笛�尔积,有规律�循,算法和代�也�难,但是很多语言都没有�供直接计算笛�尔积的方法,需�自己写大段大段的代�计算笛�尔积,python �供了一�最简�的计算笛�称积的方法(�需�一行代�),详�下�的代�:

#!/usr/bin/python3
# -*- coding: utf-8 -*-
# @file   : Cartesian.py
# @author : shlian
# @date   : 2018/5/29
# @version: 1.0
# @desc   : 用python实现求笛�尔积
import itertools

class cartesian(object):
    def __init__(self):
        self._data_list=[]

    def add_data(self,data=[]): #添加生�笛�尔积的数�列表
        self._data_list.append(data)

    def build(self): #计算笛�尔积
        for item in itertools.product(*self._data_list):
            print(item)

if __name__=="__main__":
    car=cartesian()
    car.add_data([1,2,3,4])
    car.add_data([5,6,7,8])
    car.add_data([9,10,11,12])
    car.build()

计算的结果如下:

(1, 5, 9)
(1, 5, 10)
(1, 5, 11)
(1, 5, 12)
(1, 6, 9)
(1, 6, 10)
(1, 6, 11)
(1, 6, 12)
(1, 7, 9)
(1, 7, 10)
(1, 7, 11)
(1, 7, 12)
(1, 8, 9)
(1, 8, 10)
(1, 8, 11)
(1, 8, 12)
(2, 5, 9)
(2, 5, 10)
(2, 5, 11)
(2, 5, 12)
(2, 6, 9)
(2, 6, 10)
(2, 6, 11)
(2, 6, 12)
(2, 7, 9)
(2, 7, 10)
(2, 7, 11)
(2, 7, 12)
(2, 8, 9)
(2, 8, 10)
(2, 8, 11)
(2, 8, 12)
(3, 5, 9)
(3, 5, 10)
(3, 5, 11)
(3, 5, 12)
(3, 6, 9)
(3, 6, 10)
(3, 6, 11)
(3, 6, 12)
(3, 7, 9)
(3, 7, 10)
(3, 7, 11)
(3, 7, 12)
(3, 8, 9)
(3, 8, 10)
(3, 8, 11)
(3, 8, 12)
(4, 5, 9)
(4, 5, 10)
(4, 5, 11)
(4, 5, 12)
(4, 6, 9)
(4, 6, 10)
(4, 6, 11)
(4, 6, 12)
(4, 7, 9)
(4, 7, 10)
(4, 7, 11)
(4, 7, 12)
(4, 8, 9)
(4, 8, 10)
(4, 8, 11)
(4, 8, 12)